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10m^2=860
We move all terms to the left:
10m^2-(860)=0
a = 10; b = 0; c = -860;
Δ = b2-4ac
Δ = 02-4·10·(-860)
Δ = 34400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{34400}=\sqrt{400*86}=\sqrt{400}*\sqrt{86}=20\sqrt{86}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{86}}{2*10}=\frac{0-20\sqrt{86}}{20} =-\frac{20\sqrt{86}}{20} =-\sqrt{86} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{86}}{2*10}=\frac{0+20\sqrt{86}}{20} =\frac{20\sqrt{86}}{20} =\sqrt{86} $
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